| Бейсик | Python |
|---|---|
| DIM S, N AS INTEGER S = 355 N = 0 WHILE S > 0 S = S - 20 N = N + 2 WEND PRINT N | s = 355 n = 0 while s > 0: s = s - 20 n = n + 2 print(n) |
| Алгоритмический язык | Паскаль |
| алг нач цел n, s s := 355 n := 0 нц пока s > 0 s := s - 20 n := n + 2 кц вывод n кон | var s, n: integer; begin s := 355; n := 0; while s > 0 do begin s := s - 20; n := n + 2 end; writeln(n) end. |
| Си | |
| #include<stdio.h> int main() { int s = 3 55, n = 0; while (s > 0) { s = s - 20; n = n + 2; } printf("%d\n", n); return 0; } |
Ответ: